If the uniform electric field is `3xx10^(3)hatiNC^(-1)`, then the flux of this field through a square of 10 cm on a side whose plane is parallel to the y-z- plane gt?

Options

A. `30Nm^(2)C^(-1)`
B. `60Nm^(2)C^(-1)`
C. `15Nm^(2)C^(-1)`
D. `25Nm^(2)C^(-1)`

Answer

A

Explanation

Here `E=3xx10^(3)hatiNc^(-1)`
Field is along positive direction of X-axis
Surface are `S=(10)^(2)cm^(2)=10^(-2)m^(2)`
When plane is parallel to YZ - plane, `theta=0^(@)`
`phi_(E)=ES cos theta=3xx10^(3)xx10^(-2)cos theta=30Nm^(2)C^(-1)`