When `1.0xx10^(12)` electrons are transferred from one conductor to another, a potential difference of 10 V appears between the conductors. Find the capacitance of this two conductor system.

Options

A. `2.32xx10^(-4)F`
B. `1.6xx10^(-8)F`
C. `1.2xx10^(-6)F`
D. None of these

Answer

B

Explanation

Number of electrons, `n=1.0xx10^(12)`
`therefore" Charge transferred, Q "=n e =1.0xx10^(12)xx1.6xx10^(-19)`
`=1.6xx10^(-7)C" "(because e=1.6xx10^(-19)C)`
Capacitance between two conductors,
`C=(Q)/(V)=(1.6xx10^(-7))/(10)=1.6xx10^(-8)F`