If a charge on the body is `1 nC`, then how many electrons are present on the body?

Options

A. `1.6xx10^(-19)`
B. `6.25xx10^(9)`
C. `6.25xx10^(27)`
D. `6.25xx10^(28)`

Answer

B

Explanation

Given, `q=1 nC=1xx1xx10^(-9)C(because 1nC=1xx10^(-9)C)`
`e=1.6xx10^(-19)C`
From the property of quantisation charge, q = ne
Number of electrons `n=(q)/(e)=(1xx10^(-9))/(1.6xx10^(-19))`
`=0.625xx10^(-9)xx10^(19)`
`=0.625xx10^(10)=6.25xx10^(9)`