The electric field in the space between the plates of a discharge tube is `3.24 xx 10^(4)NC^(-1)`. If mass of proton is `1.67xx10^(-27)` kg and its charge is `1.6xx10^(-19)C`, the force often the proton in the field is

Options

A. `10.4xx10^(-15)N`
B. `2.0xx10^(-23)`
C. `5.40xx10^(-15)N`
D. `5.20xx10^(-15)N`

Answer

D

Explanation

As, the force on the proton
`F=qE=1.6xx10^(-19)xx3.25xx10^(4)=5.20xx10^(-15)N`