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Two positive ions , each carrying a char...

Two positive ions , each carrying a charge `q` , are separated by a distance `d`.If `F` is the force of repulsion between the ions , the number of electrons missing from each ion will be (`e` being the charge on an electron)

A

`(4pi epsilon_(0)Fd^(2))/(e)`

B

`sqrt((4pi epsilon_(0)Fe^(2))/(d^(2)))`

C

`sqrt((4pi epsilon_(0)Fd^(2))/(e^(2)))`

D

`(4pi epsilon_(0)Fd^(2))/(e^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

Force of repulsion between the charge
`F=(kqq)/(d^(2))=(1)/(4pi epsilon_(0))(qq)/(d^(2))" where, q = ne"`
`therefore" "F=(1)/(4pi epsilon_(0))(n^(2)e^(2))/(d^(2))rArr n=sqrt((4piepsilon_(0)Fd^(2))/(e^(2)))`
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