The work done in carrying an electron from point A to a point B in an electric is 10 MJ. The potential difference `(V_(B)-V_(A))` is then

Options

A. `+2kV`
B. `-2kV`
C. `+200V`
D. None of these

Answer

D

Explanation

Work done by the field,
`W=q(-dV)=-e(V_(A)-V_(B))`
`=e(V_(B)-V_(A))=e(V_(C)-V_(A))" "(because V_(B)=V_(C))`
`rArr" "(V_(C)-V_(A))=(W)/(e)=((10xx10^(6)J))/(1.6xx10^(-19)C)`
`=6.25xx10^(25)V`