If `10^(10)` electrons are acquired by a body every second, the time required for the body to get a total charge of C will be

Options

A. 2 h
B. 2 days
C. 2 yr
D. 20 yr

Answer

D

Explanation

1 electron has a charge of `1.6xx10^(-19)C.`
`10^(10)` electrons would have a charge of
`q = n e = 1.6xx10^(-19)xx10^(10)=1.6xx10^(-9)C`
Thus, in 1s, charge accumulated `=1.6xx10^(-9)C`
So, time taken to accumulate 1C
`=(1)/(1.6xx10^(-9))=0.625xx10^(9)`
`=6.25xx10^(8)s=173611h`
`=7233" days "~~"20 yr"`