A charge q is placed at the centre of a cube of side `l` what is the electric flux passing through two opposite faces of the cube ?

Options

A. `(q)/(epsilon_(0))`
B. zero
C. `(6qL^(2))/(epsilon_(0))`
D. `(q)/(6L^(2)epsilon_(0))`

Answer

A

Explanation

Since, the charge is placed at the centre of the cube, so the electric flux, lines move out equally from all sides of the cube. Thus, the electric flux emerging from the cube is equal to `(q)/(epsilon_(0)).`