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A parallel plate capacitor is charged an...

A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential and capacitance respectively are

A

constant, decrease, increase

B

constant, decrease, decrease

C

constant, increase, decrease

D

increase, decrease, decrease

Text Solution

Verified by Experts

The correct Answer is:
C
After separation charge is constant.
Potential, `V=E.d`
Capacity, `C=(epsilon_(0)A)/(d)`
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