A capacitor or capacitance `C_(1)` is charge to a potential V and then connected in parallel to an uncharged capacitor of capacitance `C_(2)`. The fianl potential difference across each capacitor will be

Options

A. `(C_(1)V)/(C_(1)+C_(2))`
B. `(C_(2)V)/(C_(1)+C_(2))`
C. `1+(C_(2))/(C_(1))`
D. `1-(C_(2))/(C_(1))`

Answer

A

Explanation

If two capacitors having capacitances `C_(1) and C_(2)` respectively are connected in parallel, then
`C_("eq")=C_(1)+C_(2)`
The final potential difference across each capacitor
`V'(C_(1)V)/(C_(1)+C_(2))`