The `500 muF` capacitor is charged at a steady rate of `100 mu C//s`. The potential difference across the capacitor will be 10 V after an interval of

Options

A. 5 s
B. 10 s
C. 50 s
D. 100 s

Answer

C

Explanation

Charge, `Q=CV=500muFxx10V=5xx10^(-3)C`
Now, `Q=qt" to "t=(Q)/(q)`
or Time taken to raise the potential difference
`t=(5xx10^(-3))/(100xx10^(-6))=(1)/(20)xx1000s=50s`