The capacitance of a parallel plate capacitor with air as medium is `3muF`. With the introduction of a dielectric medium between the plates, the capacitance becomes `15muF.` The permittivity of the medium is

Options

A. `5C^(2)N^(-1)m^(-2)`
B. `15C^(2)N^(-1)m^(-2)`
C. `0.44xx10^(-10)C^(2)N^(-1)m^(-2)`
D. `8.845xx10^(-11)C^(2)N^(-1)m^(-2)`

Answer

C

Explanation

Capacitance of a parallel plate capacitor with air is `C=(epsilon_(0)A)/(d).` Capacitance of a same parallel plate capacitor with the introductory of a dielectric medium
`C'=(Kepsilon_(0)A)/(d)`
where k is the dielectric constant of a medium.
`therefore" "(C')/(C)=K rArr =(15)/(3)=5 and K=(epsilon)/(epsilon_(0))`
`"or "epsilon=K epsilon_(0)=5xx8.854xx10^(-12)`
`=0.4427xx10^(-10)C^(2)N^(-1)m^(-2)`