The differeence in the effective capacity of two similar capacitor when joined in series and then in paralllel is 6 `mu` F the capacity of each capacitor is

Options

A. `2muF`
B. `4muF`
C. `8muF`
D. `16muF`

Answer

B

Explanation

When two similar capacitor are joined in series, then effective capacity is
`(1)/(C_(s))=(1)/(C)+(1)/(C)=(2)/(C)`
`therefore" "C_(s)=(C)/(2)`
When joined in parallel, `C_(p)=C+C=2C`
Since, `" "C_(p)-C_(s)=6muF`
`therefore" "2C-(C)/(2)=6`
`rArr" "4C-C=12`
`"or "C=4muF`