Energy per unit volume for a capacitor having area A and separation d kept at potential diffeence V is given by : -

Options

A. `(1)/(2)epsilon_(0)(V^(2))/(d^(2))`
B. `(1)/(2epsilon_(0))(V^(2))/(d^(2))`
C. `(1)/(2)CV^(2)`
D. `(Q^(2))/(2C)`

Answer

A

Explanation

Energy density `=(1)/(2)epsilon_(0)E^(2)`
Since `E=(V)/(d)`
Therefore, energy density `=(1)/(2)epsilon_(0)((V^(2))/(d^(2)))`