A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes

Options

A. `sqrt(2C`
B. 2C
C. `(C)/(sqrt2)`
D. `(C)/(2)`

Answer

D

Explanation

The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is.
`C=(Kepsilon_(0)d)/(d)" …(i)"`
when dielectric (oil) is removed, so capacitance
`C_(0)=(epsilon_(0)A)/(d)" …(ii)"`
Comparing Eqs. (i) and (ii), we get
`C=KC_(0)`
`rArr" "C_(0)=(C)/(K)=(C)/(2)" "(because K=2)`