If the distance between the plates of parallel plate capacitor is halved and the dielectric constant of dielectric is doubled, then its capacity will

Options

A. increased by 16 times
B. increases by 4 times
C. increase by 2 times
D. reamin the same

Answer

B

Explanation

The capacity of a parallel plate capacitor is given by
`C=(Kepsilon_(0)A)/(d) prop (K)/(d)`
Hecne, `(C_(1))/(C_(2))=(K_(1))/(K_(2))xx(d_(2))/(d_(1))=(d//2)/(d)=(1)/(4)`
Therefore, `C_(2)=4C_(1)`