A 700 pF capacitor is charged by a 50 V battery. The electrostatic energy stored it is

Options

A. `17.0xx10^(-8)J`
B. `13.6xx10^(-9)J`
C. `9.5xx10^(-9)J`
D. `8.7xx10^(-7)J`

Answer

D

Explanation

`therefore` Energy stored in the condenser
`U=(1)/(2)(Q^(2))/(C)=(1)/(2)((CV)^(2))/(C)=(1)/(2)CV^(2)`
`U=(1)/(2)xx(700xx10^(-12))xx50xx50=8.7xx10^(-7)J`