A solenoid of length `0*5m` has a radius of `1cm` and is made up of `500` turns. It carries a current of `5A`. What is the magnitude of the magnetic field inside the solenoid?

Options

A. `4.39xx10^(-5)T`
B. `3.28 xx10^(-3)T`
C. `2.39 xx10^(-5) T`
D. `6.28 xx10^(-2)T`

Explanation

Given total number of turns N=500
Lenth of solenoid L=0.5 m
current I==5A
radius r=1 cm =`10^(-2) m`
use formula `B=(mu_(0)Ni)/(I)` ltvbrgt Put all the values and calucate the requuired magnitude of magnetic field
`B=4pi xx10^(-7)xx500/0.5 xx5 =628 xx 10^(-3)T`