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A galvanometer of resistance 15 Omega gi...

A galvanometer of resistance `15 Omega` gives full scale deflection for a current of 2mA. Calculate the shunt resistance needed to convert it into an ammeter of range 0 to 5A.

A

0.09 `Omega`

B

`0.08 Omega`

C

`23 Omega`

D

`0.006 Omega`

Text Solution

Verified by Experts

Given G=`15 omega`
`I_(g)=2 mA=2xx10^(-3) A, I=5A`
`therefore` shunt resistance `S=(I_(g)G)/(I-I_(g))=(2xx10^(-3)xx15)/(5-2xx10^(-3))`
`S=1006 omega`
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