In the given circuit the current is to be measured the value of the current if the ammeter shown is a galvanometer with a resistance `R_(g)=60 omega` is

Options

A. 0.99 A
B. 0.048 A
C. 0.02 A
D. 0.06 A

Explanation

Total resistance in the circuit is R=`R_(G)+3`
Given `R_(g)=60 omega`
therefore `R=60+3=63 omega`
from ohm is law `I=(V)/(R )=3/63 -0.048 A`