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What uniform magnetic enter a magnetic field applied perpendicular to a beam of electrons moving at `1.3xx10^(6) ms^(-1)` is required to make the electrons travel in a circular arc of radius 0.35 m

A

`21 xx10^(-5) T`

B

`6xx10^(-5)T`

C

`2.1 xx 10^(-5)T`

D

`6xx10^(-5)T`

Text Solution

Verified by Experts

The correct Answer is:
C

Radius `r=(mv)/(qB)`
or magnetic due to moving electron `B=(mv)/(qr)`
`=(9.1xx10^(-31)xx1.3xx10^(6))/(1.6xx10^(-19)xx0.35)=2.1xx10^(-5)T`
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