If the radius of the dees of cyclotron is r then the kinetic energy of a proton of mass m accelerated by the cycloton at an oscillating frequency v is

Options

A. `4pi^(2)m^(2)v^(2)r^(2)`
B. `4pi^(2)mv^(2)r^(2)`
C. `2pi^(2)mv^(2)r^(2)`
D. `pi^(2)mv^(2)r^(2)`

Answer

C

Explanation

Given r is the outside radius of the dees v is the speed of the particle when travelling in a path of this radis and m is the mass of proton kinetic energy of particles accelerated in a cyclotorn
`K=2pi^(2)mv^(2)r^(2)`