An electron is accelerated by a potential difference of 12000 volts. It then enters a uniform magnetic field of `10^(-3)T` applied perpendicular to the path of electron. Find the radius of path. Given mass of electron `=9xx10^(-31)kg` and charge on electron `=1.6xx10^(-19)C`

Options

A. 36.7 m
B. 36.7 cm
C. 3.67 m
D. 3.67 cm

Answer

A

Explanation

Radius `r=sqrT(2mK)/(qB)=(1)/(B)sqrt(2mV)/(q)`
`=1/10^(-3)(2xx9xx10^(-31)xx1200)/(1.6xx10^(-19))`
=0.367 m =36.7 cm