The current in the windings on a toroid ...

The current in the windings on a toroid is `2.0A`. There are 400 turns and the mean circumferential length is `40cm`. If the inside magnetic field is `1.0T,` the relative permeability is near to

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The correct Answer is:

Magnetic field `B=(mu_(0)mu_(r )Ni)/(2pi r)`
`1=(4pi xx10^(-7)xxmu_(r )xx400xx2)/(40xx10^(-2))`
`mu_(r )=400`

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