A galvanometer has a resistance of ` 3663Omega`. A shunt Sis connected across it such that (1/34) of the total current passes through the galvanometer. Then the value of the shunt is :

Options

A. 3663 `omega`
B. `111 omega`
C. `107.7 omega`
D. `3555.3 omega`

Answer

B

Explanation

shunt is a low resistance connnected in parallel with the galvanometer or ammeter

shunt is given by `S=(l_(g)G)/(l-l_(g))`
here `(l_(g))/(l)=1/34`
`rarr 1/34 =(S)/(S+G)`
`therefore S=(G)/(33)=(3663)/(33)=111 omega`