A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Options

A. `(q)/(2m)`
B. `(q omega r^(2))/(2)`
C. `(q omega)/(2m r^(2))`
D. `( q omega r^(2))/(2m) `

Answer

A

Explanation

The relation between magnetic moment `(mu_l)` and angular momentum (L) is ` mu_l=-(q)/(2m)L`
`implies (mu_l)/L=(q)/(2m)`
The negative sign indicates that the angular momentum of the electron is opposite in direction to the magnetic moment.