Let `n_(p) and n_(e)` be the number of holes and conduction electrons respectively in a semiconductor. Then,

Options

A. `n_(p) gt N_(e)` in an intrinsic semiconductor, `I lt I_(p)+I_(e)`
B. `n_(p)=n_(e)` in an extrinsic semiconductor, `I gt I_(p) +I_(e)`
C. `n_(p) =n_(e)` in an intrinsic semiconductor, `I=I_(p)+I_(e)`
D. `n_(p) gt n_(e)` in an intrinsic semiconductor, `I=0`

Answer

C

Explanation

In intrinsic semiconductors, the number of free electron, `n_(e)` is equal to the number of holes, `n_(h)`. That is `n_(e)=n_(h)=n_(i)`, where `n_(i)` is called intrinsic carrier concentration, `I=I_(p)+I_(e)`.