Oxygen is prepared by catalytic decomposition of potassium chlorine `(KClO_(3))`. Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen `(O_(2))`. How many moles and how many grams of `KClO_(3)` are required to produce 2.4 mole `O_(2)`?

Options

A. `196.0`
B. `190.6`
C. `169.0`
D. `196.2`

Answer

A

Explanation

The balanced equation is
`underset(underset(2xx(39+35.5+3xx16)=245"g")(2"mol"))(2KClO_(3)(s)+)20_(2)(g)rarr 2KCl(s) + underset(underset(2.4 "moles")(3 "mol"))(3O_(2))(g)`
`because` 3 moles of `O_(2)` Is produced by decomposition of `KClO_(3) = 245`g
`because 2.4` moles of `O_(2)` will be produced by the decompostion of ltb rgt `KClO_(3)=(245xx2.4)/3=196.0 "g"`