What volume of oxygen at N.T.P is needed to cause the complete combustion of 200 mL of acetylene ? Also calculate the volume of carbon dioxide formed.

Options

A. 300, 400
B. 500, 400
C. 400, 300
D. 400, 500

Answer

B

Explanation

`underset(underset(2xx22400" cm"^(3))(2" mol"))(2C_(2)H_(2))+ underset(underset(5xx 22400" cm"^(3))(5" mol"))(5O_(2)) rarr underset(underset(4xx22400" cm"^(3))(4" mol"))(4 CO_(2)) +2H_(2)O`
`because 2 xx22400" cm"^(3)` Of acetylene requir `O_(2)` for complete combustion
`=5xx 22400" cm"^(3)`
`200" cm"^(3)` of acetylene will require `O_(2)` for complete combustion
`=(5xx22400)/(2xx22400)xx200`
Further, `2xx22400" cm"^(3)` of acetylene produce `CO_(2)`
`= 4 xx 22400" cm"^(3)`
`therefore 200" cm"^(3)` of acetylene will produce `CO_(2)`
`=(4xx22400)/(2xx22400)xx200`
`400" cm"^(3)` at STP