If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?

Options

A. `m_(1)/m_(2)=E_(2)/E_(1)`
B. `E_(1)E_(2)=m_(1)m_(2)`
C. `m_(1)E_(2)=E_(1)m_(2)`
D. `(m_(1)+m_(2))=(E_(1)+E_(2))`

Answer

C

Explanation

The correct formulae that expresses the law of
equivalent correctly is
`m_(1)E_(2)=E_(1)m_(2)`