The system thet contains the maximum number of
atoms is

Options

A. `4.25` g of `NH_(3)`
B. 8 g of `O_(2)`
C. 2 g of `H_(2)`
D. 4 g of He

Answer

A

Explanation

Number of moles `= ("mass")/("molar mass")xxN_(A)`
`therefore` Number of atoms in `4.25` g `NH_(3)`
`= 4.25 /17 xx N_(A) xx4 = N_(A)`
Number of atoms in 8 g `O_(2)`
`O_(2) = 8/32 xx N_(A) xx 2 = N_(A)/2 `
Number of atoms in 2 g `H_(2)`
`H_(2) = 2/2 xx N_(A) xx 2=2N_(A)`
Number of atoms in 4 g He
`He= 4/4 xx N_(A) xx 1= N_(A)`
Thus, 2 g of `H_(2)` contains the maximum number of
atoms among the given.