In the synthesis of ammonia
`N_(2)(g)+3H_(2)hArr2NH_(3)(g)`
If the quantity of `N_(2)` reacted is `700mL`, the quantity of `H_(2)` and `NH_(3)` would be

Options

A. 300 mL `H_(2)` and 200 mL `NH_(3)`
B. 300 mL `H_(2)` and 300 mL `NH_(3)`
C. 300 mL `H_(2)` and 100 mL `NH_(3)`
D. 100 mL `H_(2)` and 200 mL `NH_(3)`

Answer

A

Explanation

`N_(2)(g) + 3H_(2) (g) hArr 2 NH_(3) (g)` If the quantity of `N_(2) (g)` reacted is 100 mL
`therefore` Thequantiy of `H_(2) (g)` is three times, 300 mL
and `NH_(3)` produced = 200 mL