How many moles of magnesium phosphate, `Mg_(3)(PO_(4)_(2)` will contain 0.25 mole of oxygen atoms?

Options

A. `0.02`
B. `3.125xx 10^(-2)`
C. `1.25xx 10^(-2)`
D. `2.5 xx 10^(-2)`

Answer

B

Explanation

As moles of O-atoms are contained by 1 mole
`Mg_(3) (PO_(4))_(2)`
`therefore 0.25` mole of O-atoms are present in `Mg_(3)(PO_(4))_(2)`
`=1/8 xx 0.25 = 3.125 xx 10^(-2) ` mol