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The total number of electrons present in...

The total number of electrons present in `18 mL` of water is ……

A

`6.023xx10^(25)`

B

`6.023xx 10^(24)`

C

`6.023xx18xx10^(23)`

D

`6.023xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
B
18 mL `H_(2)O = 18 g H_(2) O`
`=18/18 = 1 ` mol `H_(2)O `
`=6. 0 23 xx 10^(23)` molecules
electron in 1 mol = 10
`therefore` Total electrons in 18 mL `H_(2) O = 6. 0 2 xx 10 ^(23) xx 10`
`= 6. 02 xx10^(24)`
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