An organic compound contains 49.3 % carbon,6.84 % hydrogen and its vapour density is 73 Molecular formula of the compound is

Options

A. `C_(3)H_(5)O_(2)`
B. `C_(3)H_(10)O_(2)`
C. `C_(4)H_(10)O_(2)`
D. `C_(6)H_(9)O_(3)`

Answer

D

Explanation

Calculation of emprical formula

The empirical formula is `C_(2)H_(3)O`
Empirical formula mass `=43`
The molecular weight `=2xx` Vapour density
`n=("molecular weight")/("empirical formula weight")`
`(146)/(43)=3.3=3`
Molecular formula `=(C_(2)H_(3)O)_(3)=C_(6)H_(9)O_(3)`