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CsBr crystallizes in a body centred cubi...

`CsBr` crystallizes in a body centred cubic lattice,The unit cell length is `439.9p m` .Given that the atomic mass of `Cs=133"amu"` and that of `Br=80am u` and Avogado number being `6.02xx10^(2)mol^(-1)`the density of `CsBr` is

A

`42.5 g//cm^3`

B

`0.425g//cm^3`

C

`8.25g//cm^3`

D

`4.2g//cm^3`

Text Solution

Verified by Experts

The correct Answer is:
D
Density of CsBr, `d=(ZxxM)/(a^3xxN_A)`
Z=1
M=133+80=213
`a=436.6"pm" = 436.6xx10^(-10) cm`
`therefore " Density (d)" = ( 1xx(133xx80))/((436.6xx10^(-10))^3xx6.02xx10^23)`
`=4.25g//cm^3`
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