The volume of water to be added to `100 cm^(3)` of 0.5 `NH_(2)SO_(4)` to get decinormal concentration is

Options

A. `400cm^(3)`
B. `450cm^(3)`
C. `500cm^(3)`
D. `100cm^(3)`

Answer

A

Explanation

`N_(1)V_(1)=N_(2)V_(2)`
`0.5xx100=0.1xxV_(2)`
`V_(2)=500cm^(3)`
`:."Water to be added to "100cm^(3)" solution"`
`=500-100=400cm^(3)`