4.0g of caustic soda is dissolved in 100 cc of solution. The normality of solution is

Options

A. `0.1N`
B. `0.5N`
C. `4.0N`
D. `1.0N`

Answer

D

Explanation

`"Normality"=("gram equivalents of solute")/("volume of solution in litre")`
Given, mass of solute = 4g
`"Molecular mass of "NaOH=23+16+1=40gmol^(-1)`
`"Volume of solution"=100ml=(100)/(1000)L=0.1L`
`:."Normality"=(4//40)/(0.1)=1.0N`