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Volume of 3.6 M NaOH required to neutra...

Volume of `3.6` M NaOH required to neutralise `30cm^(3)" of "0.4M` HCI is

A

`20cm^(3)`

B

`40cm^(3)`

C

`45cm^(3)`

D

`30cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`M_(1)V_(1)=M_(2)V_(2)`
`0.6xxV_(1)=0.4xx30,V_(1)=(0.4xx30)/(0.6)=20cm^(3)`
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