At `40^(@)C` the vapour pressure of pure liquids, benzene and toluene, are `160 mm Hg` and `60 mm Hg` respectively. At the same temperature, the vapour pressure of an equimolar solution of the liquids, assuming the ideal solution will be:

Options

A. 140mm Hg
B. 110mm Hg
C. 220mm Hg
D. 100mm Hg

Answer

B

Explanation

`p_("total")=p_(1)^(@)x_(1)+p_(2)^(@)x_(2)`
`160xx(1)/(2)+60xx(1)/(2)=110mm" Hg"`