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1xx10^(3)m" solution of Pt "(NH(3))(4)Cl...

`1xx10^(3)m" solution of Pt "(NH_(3))_(4)Cl_(4) " in "H_(2)O` shows depression in freezing point by `0.0054^(@)C`. The structure of the compound will be
`("given "K_(f)(H_(2)O)=1.860km^(-1))`

A

`[Pt(NH_(3))_(4)]Cl_(4)`

B

`[Pt(NH_(3))_(3)Cl]Cl_(3)`

C

`[Pt(NH_(3))_(2)Cl_(2)]Cl_(2)`

D

`[Pt(NH_(3))Cl_(3)]Cl`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_(f)=iK_(f)m`
`0.0054=ixx1.86xx0.001`
`i=(5.4)/(1.86)=2.90~=3`
`So,[Pt(NH_(3))_(2)Cl_(2)]Cl_(2) " is the structure of the compound"`
`[Pt(NH_(3))_(2)Cl_(2)]Cl_(2)hArr[Pt(NH_(3))_(2)Cl_(2)]^(o+)+2Cl^(Θ)`
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1 xx 10^(-3) m solution of Pt(NH_(3))_(4)Cl_(4) in H_(2)O shows depression in freezing point of 0.0054^(@)C . The formula of the compound will be [Given K_(f) (H_(2)O) = 1.86^(@)C m^(-1) ]

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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-SOLUTIONS AND COLLIGATIVE PROPERTIES -Exercise 1 (Types of Solutions and Concentration of Solutions)
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