The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should be

Options

A. `98.96^(@)C`
B. `100.52^(@)C`
C. `101.04^(@)C`
D. `107.01^(@)C`

Answer

C

Explanation

`DeltaT_(b)=iK_(b)m=2xx1xx0.52=1.04`
`:.T_(b)=T_(b)^(@)+DeltaT_(b)=100+1.04`
`101.4^(@)C`