How many grams of `H_(2)SO_(4)` is/are to be dissolved to prepare 200 mL aqueous solution having concentration of `[H_(3)O^(+)]` ions is 1 M at `25^(@)C` temperature?

Options

A. `19.6g`
B. `0.98g`
C. `4.9g`
D. `9.8g`

Answer

D

Explanation

`"Molarity,"M=(w_(2)xx1000)/(M_(2)xxV("in L")),"where "w_(2)" is the mass of "`
`H_(2)SO_(4)"in g " M_(2) " is the molar mass of "H_(2)SO_(4).`
`w_(2)=(1xx98xx200)/(1000)=19.6g`
`H_(2)SO_(4)+2H_(2)OhArr2H_(3)O^(+)+SO_(4)^(2-)` But according to equation, 1 mole of `H_(2)SO_(4)` gives 2 moles of ` [H_(3)O^(+)]` ions. Thus the amount of `H_(2)SO_(4)` to prepare 200 mL solution having 1 M concentration of `H_(3)O^(+)` ions is `19.6/2=9.8g`.