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Addition of a non-volatile solute causes...

Addition of a non-volatile solute causes lowering in vapour pressure of a solvent from`0.8atm` to`0.2atm` . What is the mole fraction of solvent ?

A

`0.25`

B

`0.75`

C

`0.50`

D

Connot be calculated

Text Solution

Verified by Experts

The correct Answer is:
A
`"From Raoult's law,"(p^(@)-p_(s))/(p^(@))=("mole fraction of solute")x_(A)`
`:.x_(A)=(0.8-0.2)/(0.8)=(0.6)/(0.8)=0=75`
Hence, mole fraction of solvent `1-0.75=0.25`
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