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Density of 2.05 M solution of acetic aci...

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

A

`1.14"mol kg"^(-1)`

B

`3.28"mol kg"^(-1)`

C

`2.28"mol kg"^(-1)`

D

`0.44"mol kg"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`"Molality "(m)=(M)/(1000 " "d-MM_(1))xx100`
`M="Molarity"," "M_(1)="Molecular mass"," "d="density"`
`(2.05)/((1000xx1.02)-(2.05xx60))=1000`
`=2.28mol" "kg^(-1)`
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