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How much C(2)H(5)OH must be added to 1.0...

How much `C_(2)H_(5)OH` must be added to `1.0"L of "H_(2)O`, so that solution should not freeze at `-4^(@)F` ?
`[K_(f)(C_(2)H_(5)OH)=1.86^(@)C//m]`

A

`lt10.75g`

B

`gt494.5g`

C

`lt20g`

D

`494.5g`

Text Solution

Verified by Experts

The correct Answer is:
B
`(C)/(5)=(F-32)/(9)`
`-4^(@)F=-20^(@)CrArrDeltaT_(f)=20^(@)C`
`"From "DeltaT_(f)=K_(f).mrArrm=(20)/(1.86)=10.75m`
`"Mass of "C_(2)H_(5)OH" needed "=10.75xx46=494.5g`
Solution not to freeze at `-20^(@)C` will require more ethanol than the mass needed to freeze at `-20^(@)C`.
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How much C_(2)H_(5)OH should be added to 1 litre H_(2)O so that it will not freeze at -20^(@)C ? K_(f) =1.86^(@)C//m .

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