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A solution is obtained by mixing 300 g o...

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solutionby mass. Calculate the mass percentage of solute in the resulting solution.

A

`33.57`

B

`66.43`

C

`87.23`

D

`19.24`

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The correct Answer is:
To solve the problem of calculating the mass percentage of solute in the resulting solution, we can follow these steps: ### Step 1: Calculate the mass of solute in the first solution The first solution is a 25% solution by mass, and we have 300 g of it. - **Mass of solute in the first solution** = (25/100) × 300 g - **Mass of solute in the first solution** = 75 g ### Step 2: Calculate the mass of solute in the second solution The second solution is a 40% solution by mass, and we have 400 g of it. - **Mass of solute in the second solution** = (40/100) × 400 g - **Mass of solute in the second solution** = 160 g ### Step 3: Calculate the total mass of solute Now we can find the total mass of solute by adding the masses from both solutions. - **Total mass of solute** = Mass of solute in the first solution + Mass of solute in the second solution - **Total mass of solute** = 75 g + 160 g = 235 g ### Step 4: Calculate the total mass of the resulting solution Next, we calculate the total mass of the resulting solution by adding the masses of both solutions. - **Total mass of the solution** = Mass of first solution + Mass of second solution - **Total mass of the solution** = 300 g + 400 g = 700 g ### Step 5: Calculate the mass percentage of solute in the resulting solution Finally, we can calculate the mass percentage of solute using the formula: \[ \text{Mass percentage of solute} = \left( \frac{\text{Total mass of solute}}{\text{Total mass of solution}} \right) \times 100 \] - **Mass percentage of solute** = (235 g / 700 g) × 100 - **Mass percentage of solute** ≈ 33.57% ### Final Answer The mass percentage of solute in the resulting solution is approximately **33.57%**. ---

To solve the problem of calculating the mass percentage of solute in the resulting solution, we can follow these steps: ### Step 1: Calculate the mass of solute in the first solution The first solution is a 25% solution by mass, and we have 300 g of it. - **Mass of solute in the first solution** = (25/100) × 300 g - **Mass of solute in the first solution** = 75 g ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-SOLUTIONS AND COLLIGATIVE PROPERTIES -Exercise 2 (Miscellaneous Problems)
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  2. A solution of Al(2)(So(4))(3){d=1.253 gm//ml} contain 22% salt by weig...

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  3. A solution is obtained by mixing 300 g of 25% solution and 400 g of 40...

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  4. Which of the following aqueous solutions produce the same osmotic pres...

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  5. 138 g of ethyl alcohol is mixed with 72 g of water. The ratio of mole ...

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  6. The vapour pressure lowering caused by addition of 100 g of sucrose (m...

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  7. The mass of a non-volatile solute of molar mass 40g" "mol^(-1) that sh...

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  8. 58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 ...

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  9. The vapour pressure of chloroform (CHCl)(3) and dichlorocethene (CH(2)...

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  10. Two solutions of HCl, A and B have concentration of 0.5 N and 0.1 M re...

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  11. A solution at 20^(@)C is composed of 1.5 mol of benzene and 3.5 mol of...

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  12. The relative lowering of vapour pressure of an aqueous solution contai...

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  13. The elevation in boiling point would be highest for

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  14. 1.2 % NaCl solution is isotonic with 7.2 % glucose solution. What will...

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  15. How many grams of concentrated nitric acid solution should be used to ...

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  16. What is the osmotic pressure of 12% solution of can sugar (mol.wt. 342...

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  17. 5.5mg of nitrogen gas dissolves in 180g of water at 273 K and 1 atm pr...

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  18. A solution of 1.25of 'P' in 50g of water lawers freezing point by 0.3^...

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  19. What is the volume of ethyl alcohol (density 1.15 g/cc) that has to be...

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  20. Consider separate solutions of 0.500 M C(2)H(5)OH(aq),0.100 M Mg(3)(PO...

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