The vapour pressure of chloroform `(CHCl)_(3)` and dichlorocethene `(CH_(2)Cl_(2))` at `298 K` is `200 mm Hg ` and `415 mm Hg`, respectively. Calculate
a. The vapour pressure of the solution prepared by mixing `25.5 g` of `CHCl_(3)` and `40 g` of `CH_(2)_Cl(2)` at `298 K`.
b. Mole fractions of each components in vapour phase .

Options

A. `173.9mmHg`
B. `615.0mmHg`
C. `347.9mmHg`
D. `90.63mmHg`

Answer

D

Explanation

`" Number of moles of "CHCl_(3)`,
`n_(A)=0.213`
`" Number of moles of "CH_(2)Cl_(2),n_(B)=0.47`
`"Mole fraction of "CHCl_(3),x_(A)=(n_(A))/(n_(A)+n_(B))=0.31`
`"Mole fraction of "CH_(2)Cl_(2)`
`x_(B)=1-x_(A)=1-0.31=0.69`
`becausep_("tatal")=p_(A)x_(A)+p_(B)x_(B)`
`200xx0.31+41.5xx0.69`
`=90.63mmHg`