Two solutions of HCl, A and B have concentration of 0.5 N and 0.1 M respectively . The volume of solutions A and B required to make 2 L of 0.2 N HCl are

Options

A. `0.5L" of " A+1.5L" of " B`
B. `1.5L" of " A+0.5L" of " B`
C. `1.0L" of " A+1.0L" of " B`
D. `0.75L" of " A+1.25L" of " B`

Answer

A

Explanation

`N_(A)=0.5,V_(A)=VL("let")`
`N_(B)=M_(B)=0.1,V_(B)=(2-V)L`
From normality equation,
`NV=N_(A)V_(A)+B_(B)V_(B)`
`0.2xx2=0.5xxV+0.1xx(2-V)`
`0.4=0.5V+0.2-0.1V`
`0.4V=0.2`
`V=(0.2)/(0.4)=0.5`
`:.V_(A)=0.5L`
`" and "V_(B)=(2-05)=1.5L`