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The relative lowering of vapour pressure...

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

A

`0.70`

B

`0.30`

C

`0.125`

D

`0.07`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Raoult's law,
Relative lowering of vapour pressure = mole fraction of solute `(x_(B))=0.0125`
`because" "x_(B)=(m.m_(A))/(1000+m.M_(A))`
`:." "0.0125=(mxx18)/(1000+mxx18)`
`rArrm=(12.5)/(17.775)=0.70`
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